Dewpoint_CloudBase_Calculation.php 7596 Bytes 10-03-2016 07:34:01
Dew Point & Cloud Base Calculation
A short introduction ...
With only few (and now widely available) sensors, a lot of interesting meterological data can be calculated.
We show here what can easily be obtained with only three sensors. We use the following ones :
|MCP9808||Temperature||±0.25°C||from -40°C to +125°C
|MPL115A2||Barometer||±1 kPa||from -40°C to +105°C
✈ QFE, QNH & QFF .:. Barometric Pressure
All of them describe the barometric pressure. Whilst QFE
is the pressure at a given height, QNH
(which is used in aviation) is normalised to
a height of 0 m (sea-level). QFF
is used by meterologists and is normalised with respect to actual atmospheric situation.
QNH to QFE conversion can easily be done with the barometric height formula.
` p(h) = p(0) * (1 - (0.0065 K/m * h ) / (288.15 K) ) ^ 5.255 ` K: Kelvin, h: height in m, p in hPa, see
As our height with respect to sea-level remains constant, h = 535 m, we may replace the term with the brackets with a constant term k = 0.93818.
Replacing further p(h=535) with QFE and p(h=0) with QNH, we arrive at : QNH = QFE / 0.93818
With our measured value of p = 955 hPa (QFE), we calcualte a QNH of 1018 hPa. The nearby airport indicates 1017 hPa.
✈ Dew Point
Air is a mixture of several gases. One of these is moisture. The amount of moisture, which may be present in air is limited. The higher the temperature, the higher is the amount of moisture which may be in the air.
The relative humidity is a measure, how much of the maximum value is currently in the air. As the maximum value depends on the temperature, the relative humidity decreases with rising temperature (and vice versa).
The dew point temperature is defined as the temperature, at which the moisture is maximum (100% relative humidity). Therefore the dew point temperature is independant of the actual temperature.
There is no exact formula, but the Magnus formula yields quite accurate values.
Magnus Formula : Saturation Vapor Pressure in [hPa]
` SVP(T) = 6.1078 * 10^((a*T)/(b+T)) `
T = Temperatur in °C
a = 7.5, b = 237.3 for T >= 0
a = 7.6, b = 240.7 for T < 0 over Water (Dewpoint)
a = 9.5, b = 265.5 for T < 0 over Ice (Frostpoint)
With this result, we may calculate the Vapor Pressure in [hPa]
` VP(R,T) = R/100 * SVP(T) `
with R = Relative Humidity
And then, we can finally calculate the Temperature Dewpoint in °C
` TD(R,T) = b*v/(a-v) ` with v(R,T) = log10( VP(R,T)/6.1078 )
Credits • Links
The Visualisation uses https://www.mathjax.org/
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