From the datasheet, we know that each output (Pin 4,5) has an impedance of 1.5 kΩ.
As we use both, this adds up to 3 kΩ. Our Bandpassfilter wants to see 330 Ω for
optimal performance @ 10.7 MHz.
Keying those values into the form above, we get C1, C2 = 14.95 pF and L1, L2 = 14'799 nH.
Using the closest E12 values, we would therefore use 2 x 15 pF and 2 x 15 µH.
As we do need some dc-blocking, two additional Capaitors of approx. 47 nF shall also be
added at the output of the IC.
The simulated Ciruit ...... shows good match.
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